Rohit Sharma was in record-breaking form as India secured a scintillating series victory over Australia with a 57-run win in the seventh and final one-day international in Bangalore.
The opener’s 209 - only the third double-hundred in the 50-over format - included 16 sixes which surpassed Shane Watson’s all-time best of 15 as he passed 3,000 ODI runs and helped his side to a mammoth 383 for six.
Australia, to their credit, put up a good fight with James Faulkner, Glenn Maxwell and Watson, batting at number eight after suffering a hamstring injury while bowling, all going on the attack but they fell short of a famous victory.
The visitors - possibly wary of India’s ability to seemingly chase any score - chose to field after winning the toss but were put on the back foot by a century partnership between Rohit and Shikhar Dhawan.
After the latter was removed for 60, attention turned to ousting Rohit, but the 26-year-old played himself in nicely before accelerating late on.
He took 71 balls to reach a fifty and 114 to bring up a hundred, which came in the 38th over with the score 218 for four. But an all-out assault in the final 12 overs saw a further 164 runs shared by Rohit and Mahendra Singh Dhoni.
Faulkner saw two successive overs go for 15 and 20, with the last five overs costing 100 runs.
In response the tourists were 132 for six after 22 overs, with Brad Haddin adding 40 and Maxwell contributing an eye-catching 22-ball 60 that included seven sixes, but a defeat seemed a foregone conclusion.
But Faulkner and Watson both hit six sixes as they shared a stand of 67 in just six overs. However, Watson fell one run short of a fifty to the 22nd delivery he faced.
Faulkner went on to a 57-ball hundred - his first of his career and the fastest by an Australian - but he could not steer his side to victory as Mohammad Shami took his third scalp to complete victory.